Kitz Forum
Chat => Games => Forum Games => Topic started by: kitz on July 10, 2023, 01:05:23 PM
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Quick puzzles: riddles, brain teasers and maths logic questions.
How it works
The puzzle poster acknowledges the first person with the correct answer, who then gets the opportunity to post the next puzzle.
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What 4 days of the week start with T?
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today, tomorrow, Tuesday and Thursday
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If you include the Two days at The weekend, most days start with a 'T', unless you have a preference for Coffee of course.
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today, tomorrow, Tuesday and Thursday
Toulouse wins. \o/
Your opportunity to post the next teaser. :)
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Hey thanks Kitz, I never usually win this type of thing.
Anyway, here is my puzzle :
What king can you make if you take
the head of a lamb
the middle of a pig
the hind of a buffalo
and the tail of a dragon
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A lion?
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4candles has cracked it. Was that a little bit too easy ?
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No, not at all. The puzzle was good.
It had me thinking for a little while and had to read it a few times, before I came to the same solution as 4candles.
I suppose I should have typed in my answer also was a lion, but I didn't want to dominate the thread.
It's not meant to be really hard. It's more about having a bit of light heated fun that engages the brain cells as a bonus.
I like doing little brain teasers such as these
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Thanks once again Kitz. I think in the present circumstances we could all do with a little of that.
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Was that a little bit too easy ?
No, not really, though it helped that with all the animals in the question, the 'king' of animals soon came to mind, and I've always liked crosswords and other forms of wordplay.
Having said that, I'm going to set a number puzzle!
1 1 1 = 6 (That's three ones, not one hundred and eleven)
Make the above equation correct by adding some common arithmetic notation to the left side.
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Struggling a wee bit with this one, nearest I can get is 7 :/
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(1+1+1)! =6
Stuart
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Yes! Stuart has cracked it. :)
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d'oh. factorials!
I'd actually started to type that I couldnt even guess at the last time I used a factorial, probably not since I was at school.
Then I remembered that I had successfully completed some puzzle or other a few years ago involving factorials ago.
I was obviously more alert then :lol:
Good puzzle and well done Stuart. Your go :)
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Try this logic puzzle...
You have two ropes that each take an hour to burn, but burn at inconsistent rates. How can you measure 45 minutes? (You can light one or both ropes at one or both ends at the same time.)
Stuart
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Light:
Rope 1 both ends
Rope 2 at one end
30 mins later
Rope 1 is fully burnt
Rope 2 is half burnt with 30 min remaining.
Now light the other end of rope 2.
15 mins later (45 total mins)
Rope 2 is fully burnt.
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Yup indeed kitz you win. Your turn again...
Stuart
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A man is sentenced to death and asked if he had any final words. He was told
"If you lie, we will hang you and if you tell the truth then we shall shoot you."
What did he say to save himself?
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Oops guess that one bombed.
The answer was "You will hang me"
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I bought a car for £200.
I sold it for £400
I bought it again for £500
I sold it again for £800
How much did I make?
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£500
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Correct :)
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OK, I've got a small logic puzzle:
A blind man is alone on a desert island. He has two red pills and two blue pills. He must take exactly one red pill and one blue pill or he will die.
How does he do it?
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He halves all 4 pills and takes half of each one (purely a guess).
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Your guess is correct :)
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This is an old one. There are two doorways, one leads to certain death, the other means you are allowed to live. Two guards are guarding the doors - one of them always tells the truth, the other one always tells lies.
You are allowed to ask one question to determine which will lead you to safety - what is the one question you could ask either guard and know for certain which door to choose?.
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What door to freedom would the other guard tell me to chose?
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You have three bags, each containing two marbles.
- Bag A contains two white marbles
- Bag B contains two black marbles
- Bag C contains one white marble and one black marble.
You pick a random bag and take out one marble.
It is a white marble.
What is the probability that the remaining marble from the same bag is also white?
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2/3
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I'd say 1/2
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From Maths is fun (https://www.mathsisfun.com/puzzles/bags-of-marbles-solution.html)
Our Solution:
2/3
You know that you do not have Bag B (two black marbles) so there are three possibilities
You chose Bag A, first white marble. The other marble will be white
You chose Bag A, second white marble. The other marble will be white
You chose Bag C, the white marble. The other marble will be black
So 2 out of 3 possibilities are white.
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My reasoning was sound, then :)
This might be lowering the intellectual tone a little, but it’s my favourite numbers riddle….
Why does 6 fear 7?
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From Maths is fun (https://www.mathsisfun.com/puzzles/bags-of-marbles-solution.html)
Our Solution:
2/3
You know that you do not have Bag B (two black marbles) so there are three possibilities
You chose Bag A, first white marble. The other marble will be white
You chose Bag A, second white marble. The other marble will be white
You chose Bag C, the white marble. The other marble will be black
So 2 out of 3 possibilities are white.
Hmm, I suppose in a strict mathematical sense this is correct but the question was "What is the probability that the remaining marble from the same bag is also white?", and as the first two options above are effectively identical that's why I went for 1/2. ::)
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Hmm, I suppose in a strict mathematical sense this is correct but the question was "What is the probability that the remaining marble from the same bag is also white?", and as the first two options above are effectively identical that's why I went for 1/2. ::)
The two white marbles in bag A are physically separate. It might help to think of them as W1 and W2. There are two ways in which a white marble can be taken from bag A, either by taking W1 or by taking W2.
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The two white marbles in bag A are physically separate. It might help to think of them as W1 and W2. There are two ways in which a white marble can be taken from bag A, either by taking W1 or by taking W2.
My logic was thus:
Bag B is discounted as it only had black marbles.
If we had chosen from Bag A then we know that the other marble is white hence the answer to the question would be 1.
If we had chosen Bag C then we know the other marble is black hence then answer to the question would be 0.
(1+0)/2 = 1/2
:)
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My logic was thus:
Bag B is discounted as it only had black marbles.
If we had chosen from Bag A then we know that the other marble is white hence the answer to the question would be 1.
If we had chosen Bag C then we know the other marble is black hence then answer to the question would be 0.
(1+0)/2 = 1/2
:)
But… since you already found a white marble, you are already more likely to be holding bag A than C.
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But… since you already found a white marble, you are already more likely to be holding bag A than C.
At this point I think my tiny mind might be about to explode!
:lol:
Perhaps my logic works if the question had been "If you picked the other marble from the same bag what is the probability of it being white"?
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At this point I think my tiny mind might be about to explode!
:lol:
You are not alone! ???
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You are not alone! ???
Just to emphasise, rest assured that my own contribution (reply #32) is at a very different extreme of mathematical complexity. That said, anybody who’s not previously aware of it, yet ‘calculates’ the correct answer, earns my sincere respect. :D
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Some puzzles may have more than one answer depending on how you look at things or how you interpret the wording which can take you down a diifferent path.
I'm in the 2/3 camp, but just ended up tying myself in knots too when trying to explain it :D :D
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This might be lowering the intellectual tone a little, but it’s my favourite numbers riddle….
Why does 6 fear 7?
Because seven, eight, nine. :D
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Because seven, eight, nine. :D
Correct, of course. :)
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Maybe 7 was a 6 offender?
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Maybe 7 was a 6 offender?
:o - This is a family show you know! :lol:
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Maybe 7 was a 6 offender?
Nice alternative, but Kitz’ answer is the one presented when I first encountered the ‘riddle’, about 15-20 years ago. :)
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:D
Here's another old favourite:
A farmer with a wolf, a goat, and a cabbage must cross a river by boat. The boat can carry only the farmer and a single item. If left unattended together, the wolf would eat the goat, or the goat would eat the cabbage. How can they cross the river without anything being eaten?
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I think this works…?
First, he takes the goat to the other side. He leaves the goat there and returns alone in the boat.
Then he takes the wolf to the other side. He leaves the wolf there, but brings back the goat.
Then he takes the cabbage to the other side. He leaves the cabbage with the wolf, and returns alone.
Then he takes the wolf goat to the other side, reuniting it with wolf and cabbage.
Apols for the edit, I made a genuine slip when composing!
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Almost. In fact I think you were actually on the right track, but made a typo rather than logic error.
ETA
apols, my post crossed with your edit. You are indeed correct. Your turn :)
I could see it was likely a typo rather than the wrong logic.
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Almost. In fact I think you were actually on the right track, but made a typo rather than logic error.
Yes and I’m afraid I already edited my typo which was a little bit naughty, probably crossed with your post. :-[
Not sure if I deserve next go for that?
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Oops, like you say our posts must have crossed.
It takes me a while to type anything these days. :/
I will edit my post as I can see from your post that you had realised and corrected.
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I hope I’m not stealing Kitz’ thunder as this one is closely related to the three bags of marbles. It’s my favourite probability poser. If you want to see a discussion, find the Wikipedia page for Monty Hall problem. But be brave and pitch your answer first. ;)
Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?"
Is it to your advantage to switch your choice?
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I've been mulling this one over for some time, but usually tie myself up in a knot. It seems simple at face value. I have made some notes in notepad and keep thinking I will go back to it when my head is clearer. I normally love stuff like this.
You start off with a 1:3 chance 33%
Then offered at 1:2 chance 50% of it being door B
This is where confusion sets in as Door A was 33%
Door C has a goat
Door B has 50% of being a car/goat
Surely that should mean Door A is also 50%
Now door B is 50%, but surely when you make the decision to swap if door B is 50%, then Door A should be 50% too. I havent looked at any of the discussions yet as I'm trying to get it straight in my own head.
I keep thinking one in three so still the same odds, but no its now 50 A or B at 50%. There has to be a twist somewhere with the wording.
At face value it appears the offer to switch has no advantage... but purely because this is a puzzle I know there has to be more to it.
I think I will have to admit defeat and go look up the Monty Hall solution.
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Ref the wording, I quoted the exact text as originally published as it seemed dangerous to change anything.
I personally think it can be taken at face value. But tiny tiny hint… the wikipedia article points out that the commonly accepted solution depends upon a few assumptions that, whilst arguably obvious, are not explicitly stated…..
The host must always open a door that was not picked by the contestant.
The host must always open a door to reveal a goat and never the car.
The host must always offer the chance to switch between the originally chosen door and the remaining closed door.
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Based on the not explicitly stated statments I came to the conclusion that its Monty who has the 50% choice.
This one is quite deep. I have looked at a solution page that says the odds are better to switch. I see that this puzzle really has caused a lot of discussion.
There are alot of other pages that discuss this puzzle that Ive yet to read and I kind of get it... but I'm not yet fully convinced.
I'm still here.
You had a 1:3 choice
Monty had a 1:2 choice
Monty eliminates one of your 3
------ and its here that things blur
You could argue that you are getting a fresh roll of the dice.
Your new chances are between door A and door B meaning 50:50
The counter argument is that you have a choice of 3 doors but Marty eliminated door C
I think the twist on words that I was looking for is "is it to your advantage to switch"
That infers we are looking at roll 1 of the dice.
Door A,B,C were 1:3
Door C was 50%
,,, and Im back in knots again. Goes to look for another solution that explains it better. :lol:
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Unfortunately some sites are failing to convince me.
For example this one here that claims to show all the possible outcomes.
https://statisticsbyjim.com/fun/monty-hall-problem/
Yet I keep thinking it doesnt... as it doesnt show that Monty has a choice of 2 possible outcomes if the contestant guesses the correct door. This takes the odds to 50:1 - See my attached image showing what I think are all the possible outcomes.
I'm glad that its supposed to have puzzled Mathematical geniuses and is said to be a paradox.
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Isn’t it astonishing?
It goes back a few decades but I first came across it quite recently, last 5-10 years. I absolutely refused to accept it was advantageous to switch, iirc I was so convinced that I became downright hostile to anybody who disagreed. But I was eventually persuaded, if only because some serious mathematicians brow-beat me into it. Also, I gather it’s been proven by computer simulation.
One way I look at it that seems nearly acceptable to my remaining few brain cells, and I think the wiki page suggests this line of thought too… the door initially chosen was a 1/3 chance, and nothing can change that. You know it’s not the door that Monty opened, so to balance the odds, the door you can switch to must have a 2/3 chance?
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Yet I keep thinking it doesnt... as it doesnt show that Monty has a choice of 2 possible outcomes if the contestant guesses the correct door. This takes the odds to 50:1 - See my attached image showing what I think are all the possible outcomes.
I can see nothing wrong with your reasoning, and will ponder it, but I remain convinced (for now) that the odds improve by switching. :D
It seems Monty Hall is actually a reformulation of an article by Martin Gardner, in his Scientific American column. He called his the “Three Prisoners” problem….
https://en.wikipedia.org/wiki/Three_Prisoners_problem
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I can see nothing wrong with your reasoning, and will ponder it, but I remain convinced (for now) that the odds improve by switching. :D
I’ve thunk about this for a while now, trying to find a weakness in Kitz’ challenge. Best I can suggest is…. isn’t it the case that the event in the list is that “Monty revealed a goat”, rather than “Monty opened some specific door”? After all, he knows what’s behind each of the doors, so even if he had a choice of goats one goat was as good as the other.
I did a bit of maths and statistics in pursuit of an engineering degree, but that was many moons ago, I’d never have called myself a mathematician or statistician, so I’m decidedly unsure.
And I certainly don’t understand the notation let alone the logic in used in some of the analysis, such as quoting something called Bayes theorem, eg https://www.statisticshowto.com/probability-and-statistics/monty-hall-problem/
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This is one heck of a puzzle with many mathematicians trying to prove or disprove the theory. I'm not steadfast in either camp. I can in part believe it might be more advantageous, it's just that I haven't seen an explanation yet that has fully managed to convince me. I dont for one minute think Im going to be able to come up with a solution that no-one else before has. There's a lot of highly educated mathematical and statisticians who have worked on this. I just want to try and understand how they got there.
Whilst I haven't spent long periods of time looking at it, I do keep going back to it when I think I have a clear head, but then give in about 5 mins later. I'm not yet prepared to say Ive exhausted all arguments, I've not even fully read the wiki article yet.... Ive skimmed over it but some of it seems to be too deep.
>>such as quoting something called Bayes theorem,
I saw that and my brain exploded :lol:
Ive looked at several sites but they seems to have answers that I feel have missed some questions in my own head. There was a site where I clicked on the door so many times.. but tbh I wasnt convinced by that either - not if the doors were coded with an amount that would favour a switch.
>> isn’t it the case that the event in the list is that “Monty revealed a goat”, rather than “Monty opened some specific door”?
Yes. There's something in the wiki article that does account for it, but says it makes the odds 1/6.... so its there that I am until I brave spending some more time on it
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I tried a different method, but still stalled when it comes to Monty having a choice of 2 doors if the contestant has selected the door with the car behind. At least wikipedia makes mention of this statistic, a lot of sites dont. So Im at the stage of trying to convince myself that Monty's choice is 1/6th at this point.
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I started to think about writing a short program to simulate the problem. It would generate random sequences, accumulating do/don’t switch outcomes over numerous iterations. Pondering the code paths led me to visualise the problem in a different way….
If the contestant does not switch then winning the car depends upon his initial choice, which was 1/3.
If the contestant does switch, then he gets the opposite of what he initially chose - a goat or a car. Since the probability that he initially chose a goat was 2/3, the odds of winning the car thus becomes 2/3.
I’ve not trawled through the various links to see if any have discussed (or trashed) my latest reasoning, but I’ve been pondering it for an hour or two without changing my mind, and thought it worth sharing. :D
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If the contestant flips a coin (heads or tails) to choose if he switches, heads he switches, tails he doesn't, what is probability he wins the car?
If the contestant flips a coin (heads or tails) head is left door, tails is right door, what is the probability he wins the car?
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If the contestant flips a coin (heads or tails) to choose if he switches, heads he switches, tails he doesn't, what is probability he wins the car?
If the contestant flips a coin (heads or tails) head is left door, tails is right door, what is the probability he wins the car?
IF we accept that switching yields a 2/3 chance vs 1/3 by not switching, then I’d say that tossing a coin (either scenario) to decide whether to switch yields the average of 1/3 and 2/3, which is 1/2.
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Monty Hall has been running for well over a week, it might be time to move on.
May I suggest that Kitz deserves the honour of setting next puzzle, in recognition for huge effort expended on analysing this one?
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Seconded
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Thirded
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It certainly got me thinking and I probably may continue to ponder from time to time.
So moving on I'll post a riddle this time.
When you have three you have three.
When you have two you have two.
When you have one you have none?
What is it?
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Linked ring in a chain?
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Good answer but not the solution I'm looking for.
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Should I give you a clue?
Would you like multiple answers to select from?
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I’m afraid I have a confession on this one. I had no ideas and ready to give up and then late last evening, in a moment of drunken weakness, I sought assistance from Google. :blush:
I’m pretty sure I now know the answer but, having cheated big time, I can’t possibly offer it as my answer. :D
Neat riddle though, assuming my cheating was right. :)
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I'd have classed it as your typical xmas cracker riddle as I didn't think it was hard, but I guess its one of those if you know, then you know.
My own answer wasn't exactly the same as the given solution but near enough considering both words can mean the same thing.
I thought someone would have got it. I guess my rather cryptic clue didn't help either. ;)
I'll give it another day now that the cat is out of the bag that my last post was a clue not a question.
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:idea: , I think.
Choices?
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YAY. :yay:
Well done
Your turn :)
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Mentioning Christmas crackers helped!
OK, onward and upward...
You're alone in a dark room, with only one match and an oil lamp, a paraffin lamp and a candle.
Which do you light first?
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I think I immediately know the answer to this one, but waiting to give someone elce a chance :D
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It wouldn't by any chance be the match, would it ?
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It certainly would toulouse! :)
The stage is yours...
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Thanks 4candles. I'll give it some thought and come back later
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Ok, here we go !
I am as light as a feather, but not even the strongest person can hold me for more than around 2 minutes.
What am I ?
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I'm pondering on this, some type of gas having a large volume size too big to be able to hold.
This then reminded me of the old puzzle: Which is heavier a pound of feathers or a pound of lead? ;D
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A very angry kitten?
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Sorry, not the answer I'm looking for. Kitz was on the right lines when talking about gas.
Back again tomorrow
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Breath?
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Yes, that is correct. Over to you.
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Thanks toulouse. And thanks to kitz for the helpful hint!
OK, here's a number puzzle:
3 8 5 0 2
5 4 4 7 0
? 9 3 8 1
________
3 7 4 5 1
What is the missing digit?
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struggling a wee bit with this one :/
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Me too - I just don't get it.
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I think I may have got it. Working backwards
sum 3,15,12,21,(8+x =y)
div 3 1, 5, 4, 7, (y/3=3) so y=9 I got lost here, but decided the only logical answer was z=1. y=9 so 9/3=3. 8+x=y so 8+x=9. so 8+1=9
lol my brain hurts due to the backwards numbers and switching between 1 & 9. I'm sure there must be an easier way to show how I got to x=1
3 8 5 0 2
5 4 4 7 0
1 9 3 8 1
=============
9,21,12,15,3. SUM OF
_____________
3 7 4 5 1 DIV 3
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That's very convoluted kitz, but you got there in the end. ;D
It's essentially five columns, and the numbers below the line are the average (ie divided by 3) of each column.
So yes, ?=1, and you are the winner. :)
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Sally was born on 31st December but celebrates her birthday in summer. Why.?
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She lives in the Southern hemisphere, Australia or N Zealand.
Stuart
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Well done. The floor is yours :)
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Well done. The floor is yours :)
To be honest we have family in N Zealand so it was quite an easy suggestion ;)
I'll have a think and post later....
Stuart
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Try this....
A man has 53 socks in his drawer: 21 identical blue, 15 identical black and 17 identical red. The lights are out and he is completely in the dark. How many socks must he take out to make 100 percent certain he has at least one pair of black socks?
Stuart
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40 ?
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40 ?
Yes indeed that's correct.
You next....
Stuart
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Oh! I thought there must be a catch, or I'd missed something. :-\
OK, next one coming up as soon as I think of one...
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Yes it's 21+17=38 which possibly takes out all blue and red, then just in case +2 to ensure you have a minimum of 2 black you may have more of course.
Stuart
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OK, here's a fowl one ;)
If a hen and a half lay an egg and a half in a day and a half, how many eggs will half a dozen hens lay in half a dozen days?
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1.5, 1.5 in 1.5
6, 6 in 1.5 days
X4
24,24 in 6.
So the answer is 24.
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Eggsactly! ;) It's all about ratios.
Over to you kitz :)
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:)
Give me a wee while to find something.
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Morning, hopefully an easy one for today.
If:
2=3
3=8
4=15
5= ?
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2x2-1=3
3x3-1=8
4x4-1=15
5x5-1=24
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I originally had
2== 1*3=3
3== 2*4=8
4== 3*5=15
5== 4*6=24
but your way works too, so the floor is yours :)
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OK, Ill try :)
If you subtract the number of bits in 20Mb from the number of bits in 80Mb what are you left with?
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I keep looking and looking at this.
Double checking the capitalisation. Making sure I'm not mixing bits and bytes. Double checking the words. Double checking the sentence. Wondering if there is a reason for the embolden text. Thinking what am I missing?
Logic tells me 80Mb - 20Mb = 60Mb
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But just to make sure, lets try the long way:
1 Megabit = 1,000,000 bits
20Mb = 20,000,000 bits
80Mb = 80,000,000 bits
80,000,000 - 20,000,000 = 60,000,000
60,000,000 bits = 60Mb
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That answer is an answer, but not the one I was looking for.
I did make this puzzle up myself, and not tested on anyone before, so may be a bit (pun intended) cryptic. It will take a certain kind of character to solve it.
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The answer wouldn't be 60Mb x 8 = 480Mega bits would it ?
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My thought processes have been pretty much the same as kitz's. I'm wondering if "the number of bits" is key here.
So, forgetting the Mb, is the answer 60 million ?
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I think I covered the 60 million too and it definitely shows lower case Mb for Megabits so can't be x 8 for MegaBytes MB.
80,000,000 - 20,000,000 = 60,000,000 (bits)
so may be a bit (pun intended) cryptic. It will take a certain kind of character to solve it.
I suspected there was more to it than 80-20, hence the hesitation in making a reply. I read it many times over to see if I could spot the clue and why you had put the 20 and 80 in bold. I even read it aloud to see if I could spot the pun.
As 4candles says, I too think number of bits may be a clue.
Completely wild guesses now coming up just for the sake of elimination ...
If you subtract the number of bits in 20Mb from the number of bits in 80Mb what are you left with?
There is only 1 'bit' in the spoken word Mb. Which would leave you with 1-1= 0.
The word 20Mb has 0 bits. 0-0=0
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PS
the Pun "bit cryptic" was clever.
Is "character" another clue.. as in keyboard chars.
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Well done Kitz you got the answer correct, I will give it to you :)
The text 20Mb and 80Mb both have the same number of characters therefore the same number of bits when using ascii, ie 4x8=32 bits, 32 - 32 = 0, ie left with zero.
Apologies if a bit too abstract, but you did get it, over to you again.
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Phew got there in the end. :)
OK I'm also going off on a tangent with this one, but its a bit of fun that shouldnt be too taxing.
It's something that cropped up on my newsfeed yesterday from a Louisiana Emergency room doctor Nick Pappas.
https://www.facebook.com/reel/760463775881699
As a surgeon I've seen foreign objects in people's bodies but I've never seen this.
Can you guess what this is and where is it.If you can I will be impressed to infinity and beyond.
Screen shot as an attachment for those who cant see FB reels.
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.... and another.
Seven brothers were born two years apart.
The youngest brother is Seven.
How old is the oldest brother.?
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Can you guess what this is and where is it.If you can I will be impressed to infinity and beyond.
I found it quite amusing that Buzz Lightyear came out quite well on the x-ray - once you had turned it upside down. The big clue was "To infinity and beyond". I dont even want to think about how it got up there though. :-\
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Seven brothers were born two years apart.
The youngest brother is Seven.
How old is the oldest brother.?
This one is deliberately designed to be ambiguous.
It is supposed to make some people to ask more questions; such as what if there are twins or triplets?
However if we ignore the possibility of multiple births and jump straight into the maths,
a large percentage of people will jump to the wrong answer conclusion and say 21 having used the formula: 7+(7*2)= 21
The correct answer to the mathematics is 19: ie 7+(6*2) = 19.
Finally, note the deliberate capitalisation of Seven indicating a proper/naming noun Thus it could be that the youngest brothers name is Seven... in which case it isnt possible to calculate the eldest brothers age, when we don't know the age for any of them.
I would have accepted 19 as the correct answer but given a bonus point if anyone mentioned about the brother's name.
As the more cryptic brain teasers bombed give me a while to try and come up with something else.
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Using my l33t photoshop skillz I drew this (an exercise in finding how shaky your hands are)
How many squares are there?
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It's making my eyes pop, but I think I see 41 :-\
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I think I see 41
I'm not 100% certain on the answer for this as its a puzzle image that I made up That is very close. but not quite the answer I'm expecting.
btw for the sake of clarification this isnt intended to be a trick question.
Ive only included squares as being those with equal length sides - not quadrilaterals or rectangles that have for example 2x1 sides/
eta
The image is far from unique and gives the same answer I was anticipating.
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After several recounts - only seeing 40 today.
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yay thats what I get too. The floor is all yours :)
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Thank you kitz.
What 5 letter word, all upper case, reads the same upside down?
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I'll have to get my thinking cap on for this one.
So far I've come up with MADAM, but that doesnt read the same up side down, them so back to the drawing board :D
Ive got a list of letters that looks the same upside down, hopefully only 5 letters shouldnt be that hard. :fingers:
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Ive got a list of letters that looks the same upside down...
Hint: The question only specifies that the word should read the same upside down.
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Hint: The question only specifies that the word should read the same upside down.
SWIMS?
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Yay! - I knew you'd get it in the end :)
Over to you kitz...
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yeah.. finally lol. Thankful that i decided S was going to be my starter letter and the middle one most likely to be a vowel if the 2nd letter was a consonant, so didn't actually take that long running through possible letters that would work with S. I think the hardest part was my brain wanted to mirror letters rather than upside downing them. :D
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>> Over to you kitz. <<
I have one to post, but want to first make sure that I can solve it myself which isnt easy when you have a cat trying to knock every object from the desk to the floor and walk over the keyboard.
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I have one to post, but want to first make sure that I can solve it myself
Sorry for the delay, I didn't want to publish a puzzle that I couldn't solve myself. When I first found this brain teaser, I thought it would just take me a wee while to figure out the logic behind it and then publish.
A few days later and even after drawing on/off switches in Excel I still hadn't found a working solution. I was stumped and had to peek at the answer.
I then groaned as I'd been looking at things from the wrong angle and not thinking outside of the box.
Having not been able to find the solution myself I was a bit hesitant about publishing it. But OTOH someone may wonder what was the puzzle that stumped me. In the end I have decided to post it, but giving you the massive clue that I didn't have - don't spend too long looking for a logic pattern in the switches.
There is a lightbulb inside a closet. The door is closed, and you cannot see if the light is on or off through the door.
However, you know the light is off to start. Outside of the closet, there are three light switches. One of the switches controls the lightbulb in the closet. You can flip the switches however you want, but once you open the door, you can no longer touch the switches.
How do you figure out without a doubt which switch controls the light?